THE ELLIPTIC LOGARITHM FUNCTION
In an earlier post I have discussed the elliptic exponential function E(iu, k) = cn(u, k) +i sn(u, k) By replacing u by -iu in this function we obtain the function E(u, k). When q approaches 0, E(iu, k) reduces to the exponential function e^iu = cos u + i sin u and E(u, k) reduces to e^u. As is well-known, the inverse of the exponential function v = e^u is the logarithm function ln v =u, such that ln(1+v) = Σ (-1)^{n-1}. v^n /n (1...